Our website uses cookies to enhance your browsing experience.
to the top
close form

Fill out the form in 2 simple steps below:

Your contact information:

Step 1
Congratulations! This is your promo code!

Desired license type:

Step 2
Team license
Enterprise license
** By clicking this button you agree to our Privacy Policy statement
close form
Request our prices
New License
License Renewal
--Select currency--
* By clicking this button you agree to our Privacy Policy statement

close form
Free PVS‑Studio license for Microsoft MVP specialists
* By clicking this button you agree to our Privacy Policy statement

close form
To get the licence for your open-source project, please fill out this form
* By clicking this button you agree to our Privacy Policy statement

close form
I am interested to try it on the platforms:
* By clicking this button you agree to our Privacy Policy statement

close form
check circle
Message submitted.

Your message has been sent. We will email you at

If you haven't received our response, please do the following:
check your Spam/Junk folder and click the "Not Spam" button for our message.
This way, you won't miss messages from our team in the future.

V501. Identical sub-expressions to the …
menu mobile close menu
Analyzer diagnostics
General Analysis (C++)
General Analysis (C#)
General Analysis (Java)
Micro-Optimizations (C++)
Diagnosis of 64-bit errors (Viva64, C++)
Customer specific requests (C++)
MISRA errors
AUTOSAR errors
OWASP errors (C#)
Problems related to code analyzer
Additional information
toggle menu Contents

V501. Identical sub-expressions to the left and to the right of 'foo' operator.

Aug 13 2013

The analyzer found a code fragment that most probably has a logic error. There is an operator (<, >, <=, >=, ==, !=, &&, ||, -, /) in the program text to the left and to the right of which there are identical subexpressions.

Consider an example:

if (a.x != 0 && a.x != 0)

In this case, the '&&' operator is surrounded by identical subexpressions "a.x != 0" and it allows us to detect an error made through inattention. The correct code that will not look suspicious to the analyzer looks in the following way:

if (a.x != 0 && a.y != 0)

Consider another example of an error detected by the analyzer in the code of a real application:

class Foo {
  int iChilds[2];
  bool hasChilds() const { return(iChilds > 0 || iChilds > 0); }

In this case, the code is senseless though it is compiled successfully and without any warnings. Correct code must look as follows:

bool hasChilds() const { return(iChilds[0] > 0 || iChilds[1] > 0);}

The analyzer does not generate the warning in all the cases when there are identical subexpressions to the left and to the right of the operator.

The first exception refers to those constructs where the increment operator ++, the decrement operator - or += and -= operator are used. Here is an example taken from a real application:

do {
} while (*++scan == *++match && *++scan == *++match &&
         *++scan == *++match && *++scan == *++match &&
         *++scan == *++match && *++scan == *++match &&
         *++scan == *++match && *++scan == *++match &&
         scan < strend);

The analyzer considers this code safe.

The second exception refers to comparison of two equal numbers. Programmers often employ this method to disable some program branches. Here is an example:

#if defined(_OPENMP)
#include <omp.h>
#define omp_get_thread_num()   0
if (0 == omp_get_thread_num()) {

The last exception refers to comparison that uses macros:

#define _WINVER_NT4_    0x0004
#define _WINVER_95_     0x0004
UINT    winver = g_App.m_pPrefs->GetWindowsVersion();
if(winver == _WINVER_95_ || winver == _WINVER_NT4_)

You should keep in mind that the analyzer might generate a warning on a correct construct in some cases. For instance, the analyzer does not consider side effects when calling functions:

if (wr.takeChar() == '\0' && wr.takeChar() == '\0')

Another example of a false alarm was noticed during unit-tests of some project - in the part of it where the correctness of the overloaded operator '==' was checked:

CHECK(VDStringA() == VDStringA(), true);
CHECK(VDStringA("abc") == VDStringA("abc"), true);

The diagnostic message isn't generated if two identical expressions of 'float' or 'double' types are being compared. Such a comparison allows to identify the value as NaN. The example of code implementing the verification of this kind:

bool isnan(double X) { return X != X; }

This diagnostic is classified as:

You can look at examples of errors detected by the V501 diagnostic.